The table below shows the chances of success with and without items. I've also calculated the averge cost of one success based on a theoretical 1 million isk cost of the datacores required. This means I can also calculate the actual benefit (in terms of isk) of the item.
Chance | Average cost per success | Average benefit of item | |||
No item | 50.4% | 1,984,127 | |||
Meta 1 | 52.5% | 1,904,762 | 79,365 | ||
Meta 2 | 56.0% | 1,785,714 | 198,413 | ||
Meta 3 | 63.0% | 1,587,302 | 396,825 | ||
Meta 4 | 84.0% | 1,190,476 | 793,651 |
The average cost of datacores for me is not exactly 1 million but varies per job and varies over time depending what the datacores cost, so here are the equations to use to calculate your own table:
- The chance of success I have taken from this very useful website and the chances shown in the table above are for max skills (5/5/5 in the appropriate 2 science skills and the racial encryption skill)
- Average cost of success = (1/chance) x cost of datacores
- Average benefit of item is just a simple subtraction of the meta item you want to calculate less the cost per success with no item
As long as I pay less than the "average benefit of item" (using the actual value of my own datacores, not the illustrative 1m isk cost of datacores used in the table above, obviously) then this not only helps my profit margins but also should help me get a more reliable flow of inventions. Win/win!
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